It must be a slow day in Bedrock. I was looking at this and realized that there may be a flaw. As it is written it doesn't matter what the 'ANSWER' is as long as it starts with a 'Y' it will be true. A response of YABADABADOO would pass the test. My guess is what you really want is that ONLY 'Y' and 'YES' should be valid. In that case take the SUBSTR(ANSWER,1,1) out and just use ANSWER.. i.e. IF ANSWER ¬= 'Y' & ANSWER ¬= 'YES' THEN
-----Original Message----- From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] Behalf Of Huegel, Thomas Sent: Monday, July 07, 2008 11:32 AM To: [email protected] Subject: Re: REXX coding question. Try it this way: IF SUBSTR(ANSWER,1,1) ¬= 'Y' & ANSWER ¬= 'YES' THEN -----Original Message----- From: The IBM z/VM Operating System [mailto:[EMAIL PROTECTED] Behalf Of Howard Rifkind Sent: Monday, July 07, 2008 11:24 AM To: [email protected] Subject: REXX coding question. This is confusing me. The response to the variable 'answer' is a Y. Yet this portion of the code isn't working. Shouldn't the logic just fall thru because the response was a Y. IF SUBSTR(ANSWER,1,1) /= 'Y' | ANSWER /= 'YES' THEN DO SAY ANSWER SAY 'THE WRONG RESPONSE HAS BEEN ENTERED' SAY SAY 'PROCEDURE IS TERMINATING, PLEASE TRY AGAIN' EXIT END Thanks _____________ LEGAL NOTICE Unless expressly stated otherwise, this message is confidential and may be privileged. It is intended for the addressee(s) only. Access to this E-mail by anyone else is unauthorized. If you are not an addressee, any disclosure or copying of the contents of this E-mail or any action taken (or not taken) in reliance on it is unauthorized and may be unlawful. If you are not an addressee, please inform the sender immediately, then delete this message and empty from your trash.
