I promise I won't "hate this"!  As a matter of fact, hurray!  That helps.  I 
guess it is easy to over-think this stuff.

>>> Alan Altmark <[EMAIL PROTECTED]> 7/29/2008 10:53 AM >>>
On Tuesday, 07/29/2008 at 11:46 EDT, Richard Clapper 
<[EMAIL PROTECTED]> wrote:
> But, I needed to understand - for a subnet on a Hipersocket:  When I 
configure 
> my Linux Guest to attach to a Hipersocket, so that I can get to a z/VSE 
Stack, 
> then I have to enter the Linux Guest's IP Address to use on the 
Hipersocket, 
> and the Routing Table entries.
> 
> For example, my Hipersocket subnet is 10.0.205.0/24.  My VSE is at 
> 10.0.205.200.  Another VSE is at 10.0.205.201, another at 10.0.205.202, 
etc. 
> My Linux Guest is at 10.0.205.1.  Everything uses subnet mask 
255.255.255.0. 
> In the Linux Guest, I believe I need to enter a Routing Entry with 
Destination 
> = 10.0.205.0, and a corresponding Gateway address for that Routing 
Entry.  I am 
> not sure what value to enter in that corresponding Gateway address in 
the 
> Routing table, and why I would use that value.
> 
> On a Hipersocket, does the Routing Entry Gateway address really mean 
anything? 
> In contrast, I understand on a physical network that the Routing Table 
Gateway 
> address represents the "next hop" in getting to the physical network. 
But on a 
> Hipersocket, there is no intermediary address to go through in order to 
get to 
> those VSE stacks.

You're gonna hate this, but you're thinking too hard.  :-)  A HiperSocket 
is a LAN segment, just like an Ethernet.  Treat it like one.  "ifconfig 
hsi0 10.0.205.1 mask 255.255.255.0"  You do not need an extra routing 
table entry.  As long as Linux references one of the VSEs by its 
HiperSocket address (e.g. 10.0.205.200), the traffic will flow on the 
HiperSocket.

The general rule is that a host does not need a separate routing table 
entry for a local interface.  Additional routing table entries are needed 
only when you want to override the "natural order" of the universe.

Alan Altmark
z/VM Development
IBM Endicott

>>> 

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