Thanks,Richard. I got your point. We are not account swap disk for the 
disk space.So XSTORE is the same. :) 




From:
"Schuh, Richard" <[email protected]>
To:
[email protected]
Date:
08/20/2009 06:05 PM
Subject:
Re: where to find the real storage for a linux guest?
Sent by:
The IBM z/VM Operating System <[email protected]>



The difference is that the pages in XSTORE have been paged out to the high 
speed paging device. VM utilizes XSTORE for that purpose and for <DC (if 
you allow it). The pages cannot be referenced while paged out; they have 
to be paged in before you can access them. You should treat XSTORE just 
like you treat DASD paging devices,  not like it is the same as main 
memory.
Regards, 
Richard Schuh 
 
 

From: The IBM z/VM Operating System [mailto:[email protected]] On 
Behalf Of [email protected]
Sent: Thursday, August 20, 2009 2:12 PM
To: [email protected]
Subject: Re: where to find the real storage for a linux guest?

Thanks Mark, Dave and Thomas. But should I add XSTORE too. We use z10. And 
there is no difference between storage and xstorage. 
Or RES already includes the xstore ? 




From: 
Mark Post <[email protected]> 
To: 
[email protected] 
Date: 
08/20/2009 11:53 AM 
Subject: 
Re: where to find the real storage for a linux guest? 
Sent by: 
The IBM z/VM Operating System <[email protected]>




>>> On 8/20/2009 at  1:39 PM, <[email protected]> wrote: 
> I issued ind user XXX
> 
> USERID=TECMWS01 MACH=ESA STOR=1G VIRT=V XSTORE=NONE 
> IPLSYS=DEV 0100 DEVNUM=00017 
> PAGES: RES=00256771 WS=00256757 LOCKEDREAL=00000014 RESVD=00000000 
> NPREF=00000037 PREF=00000000 READS=00000646 WRITES=00000646 
> XSTORE=005083 READS=024650 WRITES=029733 MIGRATES=000000 
> 
> Could you tell me which one. And how to convert to MB. 

RES(IDENT) pages = 256771.  Each of those are 4KB in size.  So, 
256771*4096/1024/1024 gives you 1,003MB, or nearly 1GB.  Showing once 
again that Linux will try to use everything you give it.


Mark Post


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