After creating the canonicalized form, no matter how that form winds up,
the l= value is applied directly AFTER the canonicalization.
That is,
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
<CRLF>
is canonicalized into:
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
and l=45 turns this into:
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345678<CRLF>
12345
Tony Hansen
[EMAIL PROTECTED]
Hector Santos wrote:
> Tony Hansen wrote:
>> Stephen Farrell wrote:
>>> Ok, so we've this and we've that. Who's volunteering to
>>> craft new text for the document?
>>
>> I did so in my original note in this thread.
>
> I guess what I am not sure about is whether a final <CRLF> is always
> required in the SIMPLE c14n method.
>
> If so, then the minimum is always l=2.
>
> But consider when l > 2, does this still mean the ending 2 bytes for the
> L amount is <CRLF>?
>
> What if the actual text is larger than L?
>
> Example:
>
> 12345678<CRLF>
> 12345678<CRLF>
> 12345678<CRLF>
> 12345678<CRLF>
> 12345678<CRLF>
> <CRLF>
>
> here you have 52 bytes. I believe canonicalized text size is l=50.
>
> But what if the actual L= size defined in the DKIM-Signature: header is
> l=45? Is the canonicalized text then?
>
> 12345678<CRLF>
> 12345678<CRLF>
> 12345678<CRLF>
> 12345678<CRLF>
> 123<CRLF>
>
> ??
>
> ---
> HLS
>
>
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