> Would be thanxful if I can get an answer to the following question.
>
>In IPV6, only the source node fragments the packet, and the assembly
>happens at the destination. The fragment size is determined by a
>finding out the MTU on the path - implying that the source now knows
>the route that the packet has to take to reach the destination. My
>doubt is this: Will a datagram in UDP have to traverse a path that is
>discovered before it is sent out (since the source may have to fragment
>the packet)or will it work just like in IPV4 where its route is
>determined by routers between the source & destination?
>
>In essence, will datagrams exhibit the same behaviour as in the
>previous version of IP?
IPv6 UDP works just like IPv4 UDP with DF bit set.
- first (or a couple of) packets can get dropped due to PMTUD,
if you throw packet larger than minimum path MTU.
- if you would like to avoid PMTUD, you can try sending packet
fragmented into minimum link MTU (1280). there's an API defined for
this (see draft-ietf-ipngwg-2292bis-02, section 11.1 and 11.2)
itojun
