Yes.

The only minor adjustment I can think of to that is something called the 
“McMaster correction,” which adjusts for an oversimplification in the usual 
EXAFS method of normalization, and thus can be different for the two edges. But 
that correction is generally quite small, and the difference in it between two 
edges is even smaller.

—Scott Calvin
Sarah Lawrence College

> On Dec 3, 2014, at 7:54 AM, Badari Rao <badari....@gmail.com> wrote:
> 
> Dear All,
> 
> Suppose I have a compound, say AB. I have the EXAFS data from both A-edge as 
> well as B-edge and I am simultaneously refining these data.
> Would it be correct to force the mean square displacement of the A-B path in 
> both the edges to be the same?
> 
> -- Regards,
> Badari Narayana. A. R.
> Ph.D Student, Nanoscience and Nanotechnology,
> c/o Prof Rajeev Ranjan,
> Electroceramics Lab,
> Department of Materials Engineering,
> Indian Institute of Science.
> 
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