On Mon, Jan 6, 2014 at 11:47 AM, Merton Lister <[email protected]> wrote:
> Hello, > > I'm trying to make sense of the assortativity measures in igraph, > specficially: > > When every vertex in the graph has the same type, both assortativity and > assortativity_nominal give `NaN`. I think this is because the algorithm > assumes that there are different types of vertices by default. > > Does it make sense to interpret this scenario as equivalent to the case > where the assortativity equals to 1, as all the edges are between the same > type of vertices? > > Some clarification would be much appreciated. Thanks! > Hi, see the formulas in the manual. The PDF manual has nicer formulas, btw: http://igraph.sourceforge.net/doc/R/igraph.pdf page 19. Gabor > > Best regards, > > Merton > > > > > _______________________________________________ > igraph-help mailing list > [email protected] > https://lists.nongnu.org/mailman/listinfo/igraph-help > >
_______________________________________________ igraph-help mailing list [email protected] https://lists.nongnu.org/mailman/listinfo/igraph-help
