Tamas,Thank you so much for your help.

On Tue, Jan 20, 2015 at 12:53 PM, Tamas Nepusz <[email protected]> wrote:

> Hi,
>
> Yes, if you use -1 as a placeholder for missing attributes, igraph
> considers
> that as a new type. How about simply taking the induced subgraph of all the
> vertices for which you know the gender and then just calculating the
> assortativity on that subgraph? Or, you could assign random genders to the
> vertices where you don't know the gender, take 1000 realizations and then
> take
> the average assortativity of these 1000 realizations.
>
> > and one other question, in what condition do we get NaN ?
> For instance, if your graph has no edges, you will get a NaN. You will
> also get
> a NaN if all the types are identical.
>
> --
> T.
>
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-- 
regards
F..A
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