#$1 is the file in which contains text to be replaced
#$2 is the file which contains the text with which it is to be replaced
filename=$1
pattern=$2
lines=`wc -l $2|cut -d' ' -f1`
for i in `seq 1 $lines`
do
replacewd=`head -$i $2 | tail -1` #read line by line
echo $replacewd
head -$i $1 | tail -1 > temp #write each line $1 in temp file
sed "s/2u/${replacewd}u/" temp >> output #replace 2 and append
the output in output file
done
This could be one of the solution...
but its not very general
cheers
Prashant Batra
On 1/18/09, Prashant Batra <[email protected]> wrote:
> filename=$1
> lines=`wc -l $filename|cut -d' ' -f1` #finds no of lines in the file
> echo "no of lines in the file are $lines"
> declare -a array[2]
> for i in `seq 1 $lines`
> do
> echo $i
> array=`head -$i $filename | tail -1`
> echo $array
> done
>
>
> This could be helpful
> but the problem is that the value of array does not persist outside the
> loop.
> hope someone else could provide the answer.
>
> On 1/18/09, Sharad Birmiwal <[email protected]> wrote:
>>
>> Hi,
>>
>> I'm not gonna fix any code but I'll help you with whatever I can..
>>
>>> I don't know how many lines are present in the file.
>>
>> use "wc -l" for this
>>
>>> Q2)
>>>
>>> I have the following content on a file.I need to replace '2' in each line
>>> with a different value which are present in a file
>>
>> Looks like a complicated operation. It'll be better if you do it in
>> perl or something :p
>>
>>
>> Sharad
>>
>> >>
>>
>
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