man scanf says you can have %sa for scanf to allocate a buffer of
sufficient size and and assign the address to this buffer to the
argument(which should be a pointer to a char *).
char *user_name;
printf("Enter the name for this new user.\n");
scanf("%sa", &user_name);
On Sun, Dec 4, 2011 at 2:32 PM, Mihir Mehta <[email protected]>wrote:
> Hi all,
>
> I'm programming a terminal-based application with c, and at various
> point, I need to prompt the user for input data. For this, I use code
> like this:
>
> char user_name[STRING_SIZE];
> printf("Enter the name for this new user.\n");
> scanf("%s", user_name);
>
> This works for now, but I feel that having the string size limited
> this way (by the constant STRING_SIZE) could be a problem, and the
> scanf man page suggests that it is capable of dynamically allocating
> enough space to the character array user_name if it is called
> appropriately. However, the language of the man page is somewhat
> unclear on this point, so could someone help me out by letting me know
> what changes I need to make to my code for the desired behaviour?
>
> Thanks,
> Mihir.
>
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Tavish Naruka
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