May I ask what "load" means? Can you load a library - if so, do its exports become visible?
On Tue, Jun 2, 2009 at 4:25 PM, Abdulaziz Ghuloum <[email protected]> wrote: > > On Jun 2, 2009, at 8:48 AM, Derick Eddington wrote: > >> In order to pass through arguments when using --load, [...] > >> Or, should --load take exactly one file and multiple "--load <file>" can >> be given in sequence, so that "--" can be both a file to load and an >> escape for passing through the rest[...] > >> Full generality requires "--" to be a possible file to load.[...] > >> If --load takes exactly one file: [Now it gets annoying.] [...] > > I think this is all too complicated. > > "--load" should consume a file name and the rest of the arguments > and loads the file after setting the command-line parameter. > > If you want to load multiple files, add (load "file2") in file1, > or do (for-each load (cdr (command-line)), or whatever you want. > > I don't think doing anything more is worth the complexity. Right? > > Aziz,,, >
