Gerald Rosenberg <[EMAIL PROTECTED]> írta:
> At 06:39 PM 10/31/2008, =?ISO-8859-2?Q?Imre_Andr=E1s?= wrote:
>
> >Now how can I explicitly tell that SEQUENCE is a keyword, and not a valid ID?
>
>
> tokens { SQ; }
>
> ID: { 'SEQUENCE' }=> 'SEQUENCE' {$type = SQ}
> | ('a'..'z'|'A'..'Z')+ ;
> it with some necessary changes (please find the current grammar below).
This compiles ok (I'm still wondering about the $type and token magic), but
there is a problem with processing A ::= SEQUENCE { a, SEQUENCE, c} as input. A
MismatchedTokenException occurs instead of treating SEQUENCE as an ID.
How can I tell ANTLR that 'SEQUENCE' means a list when followed by '{',
otherwise it is an ID?
Thanks,
András
--- grammar --------------------
grammar keyword;
tokens { SQ; }
DEFINES : '::=' ;
WS : (' '|'\t')+ {skip();} ;
SEQUENCE : 'SEQUENCE';
prog: stat+ ;
stat: assignment;
assignment : leftValue DEFINES rightValue {System.out.println($leftValue.value
+ "=" + $rightValue.value);};
leftValue returns [String value]: ID {$value = $ID.text;};
rightValue returns [String value]: ID {$value = $ID.text;}| sequence {$value =
$sequence.value;};
sequence returns [String value]: SEQUENCE '{' e=rightValue {$value=$e.value;}
(',' e=rightValue {$value += $e.value;})* '}';
ID: ( SEQUENCE )=> SEQUENCE {$type = SQ;} | ('a'..'z'|'A'..'Z')+ ;
--- end of grammar ---
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