Hi Kindly Help ME.
"select a.b from t a".  I cant able to use alias. I wrote grammar for
" t as a". But i want
"t a". Kindly tel how it is possible.

On 2/26/09, Robert Soule <[email protected]> wrote:
>
> Hi,
>
> I am converting from one language to another using tree re-write rules.
> I am getting an error when both languages define the same token. For
> example:
>
> >From A.g:
> grammar A;
> options { output = AST; }
> tokens { PROGRAM; A; }
> accept : program EOF      ->   ^(PROGRAM program);
> program : ',' 'a'         -> ^(A ',' 'a');
> WHITE_SPACE      : (' '|'\t'|'\r'|'\n')+                     {
> $channel = HIDDEN; };
>
> >From B.g:
> grammar B;
> options { output = AST; }
> tokens { BPROGRAM; B; }
> accept : program EOF      ->   ^(BPROGRAM program);
> program : 'b' ','             -> ^(B 'b' ',');
> WHITE_SPACE      : (' '|'\t'|'\r'|'\n')+                     {
> $channel = HIDDEN; };
>
> >From AtoB.g:
> tree grammar AtoB;
> options { tokenVocab=A; tokenVocab=B;  ASTLabelType=CommonTree; output=AST;
> }
> accept : ^(PROGRAM program)  -> ^(PROGRAM program);
> program : ^(A ',' 'a')           -> ^(B 'b' ',');
>
>
> The error seems to occur because both A.g and B.g use a ',' literal,
> assigned
> different values in their respective .tokens files. When I reference
> the ',' literal
> in AtoB.g, I'm guessing that there is no way to tell if it is A's token or
> B's.
>
> Is there either a way to scope tokens (A::';') or is there way to
> define a common
> set of tokens that are shared by both grammars, and then import them?
>
> thank you,
> Robert
>
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>
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>

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