Hi guys,
Can somebody explain to me why this is ok in a parser grammar:
pointer
: '*' -> ^(POINTER)
;
But this is an error in a tree grammar?:
pointer
: ^(POINTER)
;
? The following appears to be the correct way to do this, and does in fact
appear to work:
pointer
: POINTER
;
But it's not clear to me why this should be so. Shouldn't both these cases
share the same syntax, either both ^(POINTER) or both POINTER?
Thanks,
--
Gary R. Van Sickle
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