As stated in the link you provided, there is nothing you have to do to get
this functionality. But 'identifier' should be a lexer rule. I guess your
grammar should be something like this:
APPLY : 'apply';
BROWSE : 'browse'
.
ID : ('A'..'Z' | 'a'..'z') ('A'..'Z' | 'a'..'z' |
'0'..'9' | '_')*;
Now, if you write a rule like
r : ID;
only ID that is not a keyword will match this.
Am I oversimplifying the problem. Did I miss something?
Cheers, Indhu
From: [email protected]
[mailto:[email protected]] On Behalf Of Avid Trober
Sent: Thursday, June 11, 2009 9:10 AM
To: [email protected]
Subject: [antlr-interest] Excluding keywords
I saw something close to my problem on the wiki,
http://www.antlr.org/pipermail/antlr-interest/2006-June/016563.html
But, I've got an "extra rule", filter. Must I resort to an action, or is
there a way to do this purely in the grammar file?
filter : // identifier, but *not* a keyword
;
keyword : APPLY
| BROWSE
| CLOSE
| OPEN
;
identifier : ('A'..'Z' | 'a'..'z') ('A'..'Z' | 'a'..'z' | '0'..'9' | '_')*
;
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