Mohan R wrote: > isdigit() takes a character as its input, not a string. Thats the > problem, change isdigit(x) to isdigit(x[0]). Thank you very much. When I compiled why didn't any warning or error message appears regards it. Since i gave char * but actual argument is char. So error msg should appear. If I am not correct, please correct me. Regards. Aravindhan K
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