Thanks.got it..exactly this is what i need.me too got the same.earlier got
the key error and gave as int(key).It worked


On Tue, Nov 5, 2013 at 4:14 PM, prathika sundaramurthy <
[email protected]> wrote:

> Hi Hari,
> Can you check if this is what you needed? As per your requirement this is
> what I have understood.
> ifile  = open('/tmp/acess_Nov5_1.csv', "rb")
> reader = csv.reader(ifile)
> print 'Key--->value'
> for i in reader:
>       if i:
>           print '%s--->%s'%(i[1],dict[int(i[1])])
> c2process
> riskmgmt
> portal
>
>
> On Tue, Nov 5, 2013 at 4:10 PM, Guruprasad <[email protected]> wrote:
>
> > Pressed send a bit too early before completing the email.
> >
> > On Tue, Nov 5, 2013 at 4:07 PM, Guruprasad <[email protected]> wrote:
> > > On Tue, Nov 5, 2013 at 3:44 PM, hari prasadh <[email protected]>
> > wrote:
> > >>
> > >>>>> dict={88:'c2process',89:'riskmgmt',95:'portal'}
> > >
> > > 'dict' is a python built-in. Not a good idea to use it to name your
> > variable.
> > > So something like my_dict = {88:'c2process',89:'riskmgmt
> >
> > my_dict = {88:'c2process',89:'riskmgmt',95:'portal'}
> >
> > Quoting the rest of the email for the completeness of the answer.
> >
> > >>>>> for i in reader:
> > >>
> > >> ...     print "dict["+i[1]+"]"
> > >
> > > print my_dict[int(i[1])] will convert the string in the 2nd column of
> > > the csv file to an integer and use it as a key, since your dictionary
> > > uses integers as keys.
> >
> > Thanks & Regards,
> > Guruprasad.
> > _______________________________________________
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> >
>
>
>
> --
> prathika sundaramurthy
> _______________________________________________
> ILUGC Mailing List:
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>



-- 
Thanks & Regards,
HariPrasadh
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