Python, of course! Just kidding, I don't know enough about Matlab to answer
that question well. Python's great for image processing though.
As far as your code, my guess is the output of split() when fed a gif isn't
in r g b format? Try running your code on a JPEG, works just fine. But with
a GIF I get the error too. Here's the output of slightly different code:
import Image
im = Image.open("test2.gif")
print im.split()
> (<Image.Image instance at 0x00EF5288>,)
As you can see, it's returning a single item list, so when you assign three
items to the output, you're getting the error.
As far as why the output of split() is so different for a GIF vs. JPEG, I
don't know.
On Mon, Feb 11, 2008 at 12:46 AM, TAN TH <[EMAIL PROTECTED]> wrote:
> which is more suitable software for Image Processing
> applications, Matlab or Python?
>
> I have tried something very simple in Python, which is
> from the pdf,
> http://www.pythonware.com/media/data/pil-handbook.pdf
> however, it gives error. anyone able to help?
>
> >>> import Image
> >>> im = Image.open("D:/test.gif")
> >>> print im.format, im.size, im.mode
> GIF (409, 460) P
> >>> r, g, b = im.split()
>
> Traceback (most recent call last):
> File "<pyshell#24>", line 1, in <module>
> r, g, b = im.split()
> ValueError: need more than 1 value to unpack
>
>
>
>
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