I can't get it to work... It's an Access db - can I perhaps mail it to you?

Regards,
Thomas

-----Oprindelig meddelelse-----
Fra: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]P� vegne af David Gregg
Sendt: 12. april 2002 15:04
Til: [EMAIL PROTECTED]
Emne: Re: [IMail Forum] OT: SQL syntax!


I don't know what database you are going against but this would work on
Oracle, MS-SQL, etc...

select aa.week, count(aa.ip)
from (select distinct a.week, a.ip
from visitors a) aa
order by 1 asc;

Regards,

David Gregg
dgSoft Internet Services
(949) 584-1514

-> Visit us at http://www.dgsoft.com
-> Web hosting, Email outsourcing, Dedicated and shared infrastructure
solutions.


----- Original Message -----
From: "Norman J. Nolasco" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, April 11, 2002 3:53 PM
Subject: RE: [IMail Forum] OT: SQL syntax!


> That will list the distinct combinations of week/ip addresses.  He
> needs the count of distinct IPs within the week.  I'm not 100% sure,
> but I think it's:
>
> SELECT Visitors.Week, COUNT(DISTINCT Visitors.IP) AS UniqueIPCount
> FROM Visitors
> GROUP BY Visitors.Week
>
> -Norm
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Jerod M.
> Bennett
> Sent: Thursday, April 11, 2002 5:02 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [IMail Forum] OT: SQL syntax!
>
>
> You need to add the DISTINCT parameter to your query.
>
> SELECT DISTINCT Visitors.Week, Visitors.IP
> FROM Visitors
> GROUP BY Visitors.Week, Visitors.IP;
>
> Jerod M. Bennett
> Director of Media Production
> Pixelpushers, Inc.
>
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]] On Behalf Of Thomas
> Testmann
> Sent: Thursday, April 11, 2002 1:18 PM
> To: [EMAIL PROTECTED]
> Subject: [IMail Forum] OT: SQL syntax!
>
>
> Hi,
>
> I have a counter on my website, which stores in a table, named
> 'Visitors', with the following fields:
>
> [Section],[Page],[Browser],[Country],[Date],[Time],[Year],[Month],[Week]
> ,[Da
> y],[Referent],[IP]
>
>
> I would then like to make a query on how many unique IPs there is,
> listed by week. However, I don't know how to do it, besides making two
> queries, 'IP1' and 'IP2', where it is the last mentioned that shows it.
> 'IP2', however makes a query on 'IP1', and I'd like to get a more
> "clean" query, that is, directly on the table.
>
> The two queries look like this:
>
> IP1:
>
> SELECT Visitors.Week, Visitors.IP
> FROM Visitors
> GROUP BY Visitors.Week, Visitors.IP;
>
>
> IP2:
>
> SELECT [IP1].[Week], Count([IP1].[IP]) AS DifferentIPs
> FROM IP1
> GROUP BY [IP1].[Week];
>
>
> I believe I should use some join or union, but can't get it to work...
>
> Really hope that somebody can help here!
>
> Thanks in advance!
>
> Regards,
> Thomas Testmann
>
>
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