This may be a rudimentary question, but I'm trying to find a way to combine z 
statistics (per observation) from 10 MI datasets into a composite z statistic 
value or composite p value for each observation.  The z statistic value comes 
from calculation of a logit model interaction effect (Ai and Norton), plotted 
against probability of the outcome, where each observation has a separate value 
for interaction effect, z statistic, and prob(outcome) (n = 25,000).
 
While I plan to average the estimates for interaction effect and prob(outcome) 
across MI sets, I'm struggling with a method for combining the z statistic 
values (or approximating a composite z stat value) on an individual observation 
level for a large dataset that appropriately accounts for the MI process.  Any 
suggestions are greatly appreciated.  Many thanks.

Craig    
 
Craig D. Newgard, MD, MPH
Assistant Professor
Department of Emergency Medicine
Department of Public Health & Preventive Medicine
Oregon Health & Science University
3181 Sam Jackson Park Road
Mail Code CR-114
Portland, OR 97239-3098
(503) 494-1668 (Office)
(503) 494-4640 (Fax)
[email protected]


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From junedsiddique <@t> gmail.com  Tue Oct 25 18:11:37 2005
From: junedsiddique <@t> gmail.com (Juned Siddique)
Date: Tue Oct 25 18:11:46 2005
Subject: [Impute] Re: the PE statistic with imputed data
Message-ID: <[email protected]>

 Hi Bill,
 I would be interested in any responses you received to this posting. One
comment I have is to look at Don Rubin's response to an earlier question
posed to this listserv (Volume 18, issue 4) concerning combining estimates
of R-squared. Rubin noted that:
 Because the standard combining rules rely on asymptotic normality, and
R-squared is a proportion of variance, asymptotic normality will be better
approximated with a transformation, like log (R-squared). Then the
standard rules can be used with the corresponding asymptotic variance for
it.
 I believe this response is relevant to your question since you are also
estimating a proportion.
 As far as which of your two methods is correct, I would appreciate any
comments you or others might have. Thanks.
 -Juned

Today's Topics:
>
> 1. the PE statistic with imputed data (Howells, William)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Tue, 27 Sep 2005 10:35:38 -0500
> From: "Howells, William" < [email protected]>
> Subject: [Impute] the PE statistic with imputed data
> To: <[email protected]>
> Message-ID:
> < 2ada428b6944da4b8f8a2fdf4e60e52a197...@exchange.wusm-pcf.wustl.edu>
> Content-Type: text/plain; charset="US-ASCII"
>
> I'm interested in calculating what some have referred to as the
> "proportion explained" statistic from two regression models with imputed
> data. This statistic comes up in the analysis of indirect effects (or
> surrogate variables, or mediation effects, depending on the literature,
> eg. Freedman and Schatzkin, Am J Epi 1992). PE = (C-C')/C where C = the
> unadjusted effect of some independent variable and C' = the same effect
> adjusted by the putative mediator. PE quantifies the proportion
> reduction in the independent variable due to mediation. If PE = 1 there
> is complete mediation. If PE = 0, there is no mediation.
>
> Calculation of standard errors for PE is controversial, depending on the
> outcome, in my case a time to event outcome. I'm using the method due
> to Lin, Fleming, and DeGruttola (Stats in Medicine 1997). But with 50
> imputed datasets. My question is whether I am combining the imputations
> correctly. I first impute my 50 datasets, n=600 each. I run the two
> regression models within each imputed dataset and obtain C and C', and
> apply the Lin et al formula to obtain both PE and se(PE). Then I use
> the usual formulas as implemented in SAS PROC MIANALYZE to obtain the
> combined PE over the m=50 imputations and the combined variance using
> the within and between imputation variance. All seems well. I think
> this is the right approach.
>
> The other way of doing it is to first calculate C and C' separately by
> averaging over the imputations and then find PE from these C and C'.
> Note that mathematically this produces a different result than the above
> method. For example, with m=2 imputations that produced (C,C') = (6,4)
> and (3,1) then PE_1 = (6-4)/6 = 1/3 and PE_2 = (3-1)/3 = 2/3. The first
> method produces (1/3 + 2/3)/2 = 1/2. The second method produces
> [(6+3)/2 - (4+1)/2] / [(6+3)/2] = (9/2-5/2)/ 9/2 = 4/9. I'm just
> looking for confirmation that the second method is incorrect. Thanks.
>
> Bill Howells, MS
> Wash U Med School, St Louis
>
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> End of Impute Digest, Vol 18, Issue 6
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