select a.id_mesin,sum(a.pemakaian_mesin * b.rate_jam)
from t_aktivitas_konvensional a,
r_mesin b
where a.id_mesin=b.id_mesin
and a.id_mesin='T1' and a.job_barang_id='2304601'
group by a.id_mesin
On 7/20/06, Antonius Didik HDS <[EMAIL PROTECTED]> wrote:
>
>
> Hi All
>
> Ada yang bisa bantu , saya ingin mengalikan hasil operasi 'sum' dengan
> variable seperti berikut
>
> SQL> select id_mesin, sum(pemakaian_mesin) from
> t_aktivitas_konvensional
> 2 where id_mesin='T1' and job_barang_id='2304601'
> 3 group by id_mesin;
>
> ID_MESIN SUM(PEMAKAIAN_MESIN)
> ---------- --------------------
> T1 9
>
> SQL> desc r_mesin;
> Name Null? Type
> ------------------------------- -------- ----
> ID_MESIN NOT NULL CHAR(10)
> NAMA_MESIN VARCHAR2(100)
> RATE_JAM NUMBER(10,2)
>
>
>
> bisakah kita mengalikan hasil 'sum(pemakaian_mesin)' dengan rate_jam
> pada table r_mesin?
> Tolong bantuannya?
>
>
>
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