Pak Agus dan Pak Wawan, terima kasih ya atas pencerahannya, membantu banget 
nih.... Thanx

Agus Sukayat <[EMAIL PROTECTED]> wrote:                                  Saya 
mencoba dengan cara yang lain tapi hasilnya sama. Mudah2an membantu
 
 select a.DNAME,count(b.ENAME) jml_emp,NVL(TO_CHAR(AVG(b.sal),
 '99999.99'), 'No average') avg_sal,nama,c.sal,c.job
 
 from dept a,emp b,(select deptno,ename nama,sal,job from emp)c
 
 where a.DEPTNO = b.DEPTNO(+)
 
 and   a.DEPTNO = c.DEPTNO(+)
 
 group by a.DNAME,nama,c.sal,c.job
 
 order by a.dname
 
 ________________________________
 
 From: [email protected] [mailto:[EMAIL PROTECTED]
 On Behalf Of wawan mulyawan
 Sent: 28 Februari 2007 11:43
 To: [email protected]
 Subject: RE: [indo-oracle] Tolong dunk...
 
 Kalau di liat dari querynya ini , sepertinya mau membandingkan salary
 dari seseorang dengan rata rata salary di departemen yang bersangkutan
 Makanya harus ada 2 employes , satu untuk orang yang dibandingkan satu
 untuk menghitung rata-rata salary di departemen itu.
 
 Semoga membantu
 
 Ti
 Mulyawan
 
 -----Original Message-----
 From: [email protected] <mailto:indo-oracle%40yahoogroups.com>
 [mailto:[email protected]
 <mailto:indo-oracle%40yahoogroups.com> ]
 On Behalf Of bapux oke
 Sent: Wednesday, February 28, 2007 11:08 AM
 To: Indo Oracle
 Subject: [indo-oracle] Tolong dunk...
 
 Dear all,
 
 Saya punya query seperti ini, 
 
 SELECT d.department_id, d.department_name, count(e1.employee_id)
 employees,
 NVL(TO_CHAR(AVG(e1.salary), '99999.99'), 'No average') avg_sal,
 e2.last_name, e2.salary, e2.job_id
 FROM department d, employees e1, employees e2
 WHERE d.department_id = e1.department_id(+)
 AND d.department_id = e2.department_id(+)
 GROUP BY d.department_id, d.department_name, e2.last_name, e2.job_id
 
 Nah yang aku ngga ngerti kenapa harus ada 2 employees, kenapa ngga
 langsung aja ?
 
 Mohon penjelasannya ya, thanx before.
 
 Hendra
 
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