makasih ya mas Awaluddin Hamid..

--- Awaluddin Hamid <[EMAIL PROTECTED]> wrote:

> Salah satu cara mungkin harus dibuatkan FUNCTION
> (belum cek dari segi 
> performans) :
> 
> SQL> CREATE TABLE detail (
>   2  group_id NUMBER(1),
>   3  kd_product VARCHAR2(4),
>   4  qty NUMBER(5));
> Table created.
> 
> SQL> INSERT INTO detail VALUES (1,'0001',4);
> 1 row created.
> SQL> INSERT INTO detail VALUES (1,'0002',5);
> 1 row created.
> SQL> INSERT INTO detail VALUES (2,'0005',1);
> 1 row created.
> SQL> INSERT INTO detail VALUES (3,'0003',2);
> 1 row created.
> SQL> INSERT INTO detail VALUES (3,'0004',2);
> 1 row created.
> SQL> INSERT INTO detail VALUES (3,'0008',9);
> 1 row created.
> 
> SQL> CREATE OR REPLACE FUNCTION v_2_h (n IN NUMBER)
> RETURN VARCHAR2 IS
>   2    x VARCHAR2(1000);
>   3    BEGIN
>   4      x := '';
>   5      FOR rec IN (SELECT * FROM detail WHERE
> group_id = n ORDER BY 
> kd_product) LOOP
>   6        x := x||TO_CHAR(rec.qty)||'
> '||rec.kd_product||' '||'+ ';
>   7      END LOOP;
>   8      RETURN RTRIM(x,' + ');
>   9    END v_2_h;
>  10  /
> Function created.
> 
> SQL> SELECT v_2_h(group_id) penjualan FROM detail
>   2  GROUP BY group_id;
> 
> PENJUALAN
>
-------------------------------------------------------
> 4 0001 + 5 0002
> 1 0005
> 2 0003 + 2 0004 + 9 0008
> 
> hth,
> AH
> 
> abe ashfi wrote:
> >
> >
> > Dear all,
> > Tolong saya dunk..
> >
> > saya punya table detail, datanya
> >
> > group_id kd_product qty
> > 1 0001 4
> > 1 0002 5
> > 2 0005 1
> > 3 0003 2
> > 3 0004 2
> > 3 0008 9
> >
> > saya mau query dan hasilnya itu akan tampil secara
> > horizontal.
> >
> > penjualan
> > ---------------
> > 4 0001 + 5 0002
> > 1 0005
> > 2 0003 + 2 0004 + 9 0008
> >
> > gimana ya ??
> >
> > tolong ya para master oracle indonesia.
> >
> > Bravo Oracle
> >
> >
>
__________________________________________________________
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> > to amazing places on Yahoo! Travel.
> > http://travel.yahoo.com/
> <http://travel.yahoo.com/>
> >
> >  
> 



 
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