I found this question interesting, since I'm about to address it in a CVS wrapper I'm writing...
Marc Tessier wrote: > I am wandering if there is any options to extract the most recent > version of a list of TAG? I have tag A, B, C and the I want to get the > most recent files of all three in one cvs checkout or cvs export so I > don't have to check the files version one by one. Larry replied: > No. You're expected to tag all the files in a module, > not just some of them. Perhaps I'm answering a different question. Here's my first solution: $ cvs checkout -r C f1 f2 f3 ... $ cvs checkout -r B f1 f2 f3 ... $ cvs checkout -r A f1 f2 f3 ... Where the first checkout gets the files with tag C. The second checkout replaces any file that has a B tag (and leaves behind any file that should be deleted as-of B I think). The third command overlays all the files tagged with A. While this approach is "wasteful" in that it can fetch 3 different versions of the same file, it meets your criteria for not having to think very hard to make it work right. A scripted approach, which would be more efficient is to collect the list of files and revisions first, and then get only the "good" ones. $ cvs -n checkout -r C <<-- returns the list that has tag C. $ cvs -n checkout -r B <<-- returns the list that has tag B. $ cvs -n checkout -r A <<-- returns the list that has tag A. Armed with the 3 lists, you can only fetch each file once. Though I don't have an example database handy with deleted files, so I can't say what to do about discarding them from the list. -CTH _______________________________________________ Info-cvs mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/info-cvs
