Hi there,

WinCVS newbie here. I can login to the CVS repository from Linux terminal fine. But cannot figure out a way to connect to CVS repos from winCVS 1.3.13 or 1.3.14 on a XP box.

I followed the very out-dated User-Guide for version 1.1 by Don Harper (June 1, 1999). I actually one time could connect to one of my trial CVS repository, and even checked out a module by fumble-mumble "accident", rather than a WAY. Now I want to sort out the steps to get winCVS to connect to CVS, but I cannot do it again. \

The winCVS start up message looks link this

CVSROOT: [EMAIL PROTECTED]:/path/to/CVSrootDir (password authentication)
Python 2.3.3 (#51, Dec 18 2003, 20:22:39) [MSC v.1200 32 bit (Intel)] on win32
TCL is available, shell is enabled : help (select and press enter)


/path/to/CVSrootDir is where the CVSROOT and my modules live.

When I supposedly supply everything correctly to winCVS, I will get

cvs -d :pserver:[EMAIL PROTECTED]:/path/to/CVSrootDir login
Logging in to :pserver:[EMAIL PROTECTED]:2401:/path/to/CVSrootDir
cvs [login aborted]: cvs: no such user
Fatal error, aborting.

***** CVS exited normally with code 1 *****


When I supply a wrong password, I will get

cvs -d :pserver:[EMAIL PROTECTED]:/path/to/CVSrootDir login
Logging in to :pserver:[EMAIL PROTECTED]:2401:/path/to/CVSrootDir
cvs [login aborted]: authorization failed: server 129.15.161.90 rejected access to /path/to/CVSrootDir for user yanglong

***** CVS exited normally with code 1 *****


When I supply a non-existence repository, I will get (whether with correct password or not)

cvs -d :pserver:[EMAIL PROTECTED]:/path/to/CVSrootDirX login
Logging in to :pserver:[EMAIL PROTECTED]:2401:
/path/to/CVSrootDirX
cvs [login aborted]: /path/to/CVSrootDirX: no such repository

***** CVS exited normally with code 1 *****


I tried stop and start WinCVS again and again. No difference. Well, the exactly same user, password and /path/to/CVSrootDir works on a Linux box just fine. I know something is set incorrectly in my winCVS. Can you tell me what could be the problem? Thanks.

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