Ted Zlatanov <[email protected]> writes: > Let's debug it. Run the following in a clean (emacs -q) instance: > > (require 'epa-file) > (require 'auth-source) > (require 'cl) > (epa-file-enable) > (setq auth-source-debug t ; use `message' to log messages > epa-file-cache-passphrase-for-symmetric-encryption t > auth-sources '((:source "~/.authinfo.gpg" :host t :protocol t))) > (auth-source-user-or-password "login" "richardriley.net" "imap") > > What does the last call return (should be your login name)? What's in > *Messages*? > > Thanks > Ted
It returns my login name ok. *Messages* just has auth-source-user-or-password: found (login)=(shamrock) for richardriley.net (imap) "shamrock" I also got prompted for a symmetric password to unlock the authinfo.gpg Note that my login name for the remote host is, in this case, the same as my local login id. _______________________________________________ info-gnus-english mailing list [email protected] http://lists.gnu.org/mailman/listinfo/info-gnus-english
