Sorry, I meant qRegisterMetaTypeStreamOperators<QImage>()
On Thu, May 17, 2018 at 2:01 PM, Jean-Michaël Celerier <
> > The problem is that QVariant doesn't know how to call it.
> Is there a reason why calling qRegisterStreamOperators<QImage>() would't
> work ?
> Jean-Michaël Celerier
> On Wed, May 16, 2018 at 11:52 PM, Thiago Macieira <
> thiago.macie...@intel.com> wrote:
>> On Wednesday, 16 May 2018 14:38:08 PDT Jérôme Godbout wrote:
>> > You will need to provide your own
>> > QDataStream& operator<<(QDataStream& ds, const QImage& img)
>> That's not needed (and won't compile). It already exists.
>> The problem is that QVariant doesn't know how to call it. So when you
>> have a
>> QImage inside a QVariant and you try to serialise that QVariant, you get
>> nothing useful.
>> Thiago Macieira - thiago.macieira (AT) intel.com
>> Software Architect - Intel Open Source Technology Center
>> Interest mailing list
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