Hello Phil,
Tuesday, July 8, 2003, 11:11:49 PM, you wrote:
PD> Is there a function that can be used to retrieve the name of a statically
PD> called child class from within an inherited method? debug_backtrace() works
PD> for this purpose, but I've seen people say that it is slow. Consider the
PD> example code below. Is this a planned feature for PHP 5, or could this
PD> possibly make it into 4.x? What options do I have?
PD> <?
PD> class a
PD> {
PD> function test_backtrace()
PD> {
PD> $bt = debug_backtrace();
PD> echo "class pre: ".__CLASS__."\n";
PD> echo "class bt: ".$bt[0]["class"]."\n";
PD> echo "class get_class: ".get_class($this)."\n";
PD> }
PD> }
PD> class b extends a
PD> {
PD> }
PD> echo "** static: \n";
PD> b::test_backtrace();
PD> $b = new b();
PD> echo "** object: \n";
$b->>test_backtrace();
?>>
PD> Output Looks Like:
PD> ** static:
PD> class pre: a
PD> class bt: b
PD> class get_class:
PD> ** object:
PD> class pre: a
PD> class bt: b
PD> class get_class: b
- the method is defined in class a so pre is correct
- backtrace @[0] sees the top caller class that's b that's correct
- get_class($var) sees the class of the variable. In you static case that is
NULL which doesn't have a class and in your object case that's b. Therfore
this is also correct.
Everything show is correct so far. The only problem is that test_backtrace()
could be called static without being defined as such.
PD> Perhaps get_class() could return the expected class name when
PD> called without arguements?
This is nonsense. NULL does not have a class type.
Best regards,
Marcus mailto:[EMAIL PROTECTED]
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