Read it:
void *memmove(void *s1, const void *s2, size_t n);
If s1 and s2 overlap, all bytes are copied in a preserving manner (unlike memcpy())
And anwer the question: are s1 and s2 overlap in the str_repeat() ? Why don't use memcpy() instead of memmove() ?
===========cut============= --- string.c Thu May 13 20:44:32 2004 +++ string_str_repeat.c Fri Jun 11 17:40:47 2004 @@ -3581,7 +3581,7 @@
while (e<ee) {
l = (e-s) < (ee-e) ? (e-s) : (ee-e);
- memmove(e, s, l);
+ memcpy(e, s, l);
e += l;
}
}===========cut=============
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