On Sat, Feb 8, 2025, at 00:19, Larry Garfield wrote: > On Fri, Feb 7, 2025, at 4:54 PM, Rob Landers wrote: > > > Put another way, what is the order of operations for this new operator? > > > > For example, what is the output of > > > > $x ? $y |> strlen(…) : $z > > > > $x + $y |> sqrt(…) . EOL > > > > Etc. > > > > I noticed this seems to be missing from the RFC. As a new operator, I > > think it should be important to specify that. > > > > — Rob > > Pipe deliberately binds fairly low, so most other operators will happen > first. Including +, ?? and ? :, for which there are tests: > > https://github.com/php/php-src/pull/17118/files#diff-81789df7e324801626ef4ef8f629cc95dceed4c09073a2b58b70c811bf776904 > > https://github.com/php/php-src/pull/17118/files#diff-56cbcf85bd7f68fa7a1f837eb15dcc536576986f366976f9642ad20867c471fd > > https://github.com/php/php-src/pull/17118/files#diff-775c14f54cd1a27719d30bfab62024aeb1625bc3f3621fa0e7c16fb1c7957fdd > > So in the examples above, the second would add $x and $y first, then > square-root the result. The first, I think would probably need parens to > avoid being invalid but I'd have to try it to be sure. > > --Larry Garfield >
It might be good to specify it in the RFC so if there are any strange behavior, decades from now, there will be an intent to figure out if it is a feature or a bug. As to the ternary, it is the difference between that example being valid and this `$x |> $x > 3 ? foo(…) : bar(...) |> baz(…)` making sense or not. Personally, I wouldn’t write this code and would use parens to disambiguate, but it’d be handy to know when doing code reviews of authors who don’t. — Rob
