04.02.2026 15:16, Oleksii Bulba пишет:

One question about semantics: what would be the expected behavior if there is another pipe operand after |return|? For example:

|$foo |> return |> bar(...);|

Would this be a compile-time error, a no-op after |return|, or is |return|intended to be a hard terminal in the pipe chain by definition?

Best regards,
Oleksii

This would lead to parse-time time error, `return |> ` is not valid grammar sequence.

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