On Wed, 20 Jul 2005, Andrey Nikolaev wrote:
> function &a() {
> if(1==2)
> return new B; //some reference...
> else
> return null; //error, we cant create B
> }
> $b_instance = a();
> ?>Why are you returning by reference in the first place here? "new B" already creates a copy. Derick -- Derick Rethans http://derickrethans.nl | http://ez.no | http://xdebug.org -- PHP Internals - PHP Runtime Development Mailing List To unsubscribe, visit: http://www.php.net/unsub.php
