php -r is equivalent of calling eval() in php code. See
http://php.net/eval for details.
Edin
Richard Lynch wrote:
This is such minutiae, but I needed a break...
The docs say final ?> is not needed, and final ; is not needed:
http://php.net/manual/en/language.basic-syntax.instruction-separation.php
It does not address what happens if BOTH are missing, however.
It would seem that with both missing...
-bash-2.05b$ cat temp.php
<?php
echo 'hello'
-bash-2.05b$
php -q temp.php
you get a syntax error:
Parse error: parse error, unexpected $end, expecting ',' or ';'
This is fine, of course.
We'll call it a feature, even, I guess.
But, for me, it feels decidedly "odd" when I do:
php -r "echo 'hello'"
and get:
Parse error: parse error, unexpected $end, expecting ',' or ';'
I mean, for some reason, I just expected that the "optional"
semi-colon at the end was, well, optional...
I mean, -r runs the code without me needing to add <?php and ?>
It's not like I'm relying on the optional ?> at the end of a file
feature.
It's a different animal.
php -r is "adding in" both <?php and ?> for me, in my mind, at least.
I just sort of expected that the -r getting rid of <?php and ?> didn't
"count" against the ?> OR ; being optional, and I figured the ; was
still optional.
Am I being too petty? :-^
I'm not filing this as bug report without some feedback, that's for sure!
Actually, I'm just interested to see how others think about this.
I don't even like leaving off ?> nor ; in PHP source code. I think
it's just a sign of sloppy coding -- even if it does mean that I can't
get that perfectly-align HTML coming out.
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