On 14 March 2011 15:18, Martin Scotta <[email protected]> wrote:
> <?php
> function test($str) {
> static $re = '/(^|[^\\\\])\'/';
> static $change = '$1\\\'';
>
> echo $str, PHP_EOL,
> preg_replace($re, $change, $str), PHP_EOL, PHP_EOL;
> }
>
> test("str '' str"); // bug?
> test("str \\'\\' str"); // ok
> test("'str'"); // ok
> test("\'str\'"); // ok
>
Your regex is ...
(^|[^\\\\])'
Options: case insensitive; ^ and $ match at line breaks
Match the regular expression below and capture its match into
backreference number 1 «(^|[^\\\\])»
Match either the regular expression below (attempting the next
alternative only if this one fails) «^»
Assert position at the beginning of a line (at beginning of the
string or after a line break character) «^»
Or match regular expression number 2 below (the entire group fails
if this one fails to match) «[^\\\\]»
Match a single character NOT present in the list below «[^\\\\]»
A \ character «\\»
A \ character «\\»
Match the character “'” literally «'»
I think [^\\\\] is wrong and you want it to be ...
(?!\\\\)
or
(?!\\{2})
With that, the output is ...
str '' str
str \'\' str
str \'\' str
str \\'\\' str
'str'
\'str\'
\'str\'
\\'str\\'
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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