Will this work:
array('foo', 'bar')('arg1', 'arg2')
?
On Wed, Jun 8, 2011 at 3:48 PM, Christian Kaps
<[email protected]> wrote:
> On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote:
>>
>> On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena <[email protected]> wrote:
>>>
>>> class foo {
>>> public function __construct() {
>>> $this->bar = function () { return 1; };
>>> // $this->bar(); // error
>>> $x = $this->bar;
>>> $x(); // ok
>>>
>>> $this->bar = array($this, 'baz');
>>> // $this->bar(); // error
>>> $x = $this->bar;
>>> $x(); // ok
>>> }
>>> public function baz() {
>>> echo 'baz';
>>> }
>>> }
>>
>> What he meant was passing an existing method as a callback if you
>> don't invoke it, i.e. passing "$this->bar" instead of array($this,
>> "bar"). I don't know how hard it'd be to achieve, but it sounds pretty
>> awesome to me.
>>
>> Cheers
>
> Yep, just what I meant.
>
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