When the IOIO is not connected, all its pins are floating.
The answer to your questions depends on what you're actually trying to
accomplish.
If I may second-guess from your question, you are probably trying to
generate a 5V digital output and you want its default state to be LOW.
What you can do about this is either:
- Easiest: do you actually NEED a 5V signal on the output? If your
device can function OK with 3.3V, then all you would need is to use the pin
in push-pull ("normal") more, and have a weak pull-down resistor on your
signal.
- Otherwise, add a p-channel FET on your output and configure it to have
the correct default state (using a pull-up to 5V on the gate and a
pull-down on the output). This will have a side effect of inverting your
signal, which can easily be mitigated in software.
On Fri, Jan 17, 2014 at 2:07 PM, Peakon <[email protected]> wrote:
> Sorry small correction it is 5V not 3V when IOIO is not connected.
>
> On Friday, 17 January 2014 21:50:37 UTC, Peakon wrote:
>>
>> Hi,
>>
>> I use 5 GPIO pins in open drain mode as outlined in IOIO wiki. When IOIO
>> is switched on but not connected I could measure about 3 V on the pins. How
>> can I set them as low (0V ) when IOIO is not connected?
>>
>> Eddie
>>
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