What's the question? What would happen is what what you've coded... If this method gets called periodically, the pin will get closed and open all the time, and would not produce a stable output when in output mode.
On Mon, Mar 3, 2014 at 1:35 PM, Tim Frisch <[email protected]> wrote: > Or this code; for example. > if (!modeButton_.isActivated()) { > pinI9.close(); > pinO9 = ioio_.openDigitalOutput(9,false); > pinO9.write(true); > } else if (modeButton_.isActivated()) { > pinO9.close(); > pinI9 = ioio_.openDigitalInput(9); > try { > if (pinI9.read()) { > testerReader.setText("ON"); > } else { > testerReader.setText("OFF"); > } > } catch (InterruptedException e) { > // TODO Auto-generated catch block > e.printStackTrace(); > } > } > > On Monday, March 3, 2014 3:30:46 PM UTC-6, Tim Frisch wrote: >> >> What would happen if I were to open a pin as both input and output and >> read/write to them depending on a switch's state? >> > -- > You received this message because you are subscribed to the Google Groups > "ioio-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/ioio-users. > For more options, visit https://groups.google.com/groups/opt_out. > -- You received this message because you are subscribed to the Google Groups "ioio-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/ioio-users. For more options, visit https://groups.google.com/groups/opt_out.
