On Fri, Sep 14, 2018 at 03:30:24PM +0100, Robin Murphy wrote:
> All we need is to wire up .flush_iotlb_all properly and implement the
> domain attribute, and iommu-dma and io-pgtable-arm will do the rest for
> us. Rather than bother implementing it for v7s format for the highly
> unlikely chance of that being relevant, we can simply hide the
> non-strict flag from io-pgtable for that combination just so anyone who
> does actually try it will simply get over-invalidation instead of
> failure to initialise domains.
> 
> Signed-off-by: Robin Murphy <robin.mur...@arm.com>
> ---
>  drivers/iommu/arm-smmu.c | 40 +++++++++++++++++++++++++++++++++-------
>  1 file changed, 33 insertions(+), 7 deletions(-)
> 
> diff --git a/drivers/iommu/arm-smmu.c b/drivers/iommu/arm-smmu.c
> index fd1b80ef9490..aa5be334753b 100644
> --- a/drivers/iommu/arm-smmu.c
> +++ b/drivers/iommu/arm-smmu.c
> @@ -246,6 +246,7 @@ struct arm_smmu_domain {
>       const struct iommu_gather_ops   *tlb_ops;
>       struct arm_smmu_cfg             cfg;
>       enum arm_smmu_domain_stage      stage;
> +     bool                            non_strict;
>       struct mutex                    init_mutex; /* Protects smmu pointer */
>       spinlock_t                      cb_lock; /* Serialises ATS1* ops and 
> TLB syncs */
>       struct iommu_domain             domain;
> @@ -863,6 +864,9 @@ static int arm_smmu_init_domain_context(struct 
> iommu_domain *domain,
>       if (smmu->features & ARM_SMMU_FEAT_COHERENT_WALK)
>               pgtbl_cfg.quirks = IO_PGTABLE_QUIRK_NO_DMA;
>  
> +     if (smmu_domain->non_strict && cfg->fmt != ARM_SMMU_CTX_FMT_AARCH32_S)
> +             pgtbl_cfg.quirks |= IO_PGTABLE_QUIRK_NON_STRICT;

Does this mean we end up over-invalidating when using short-descriptor?
Could we not bypass the flush queue in this case instead? Ideally, we'd
just reject the domain attribute but I don't know if we know about the
page-table format early enough for that. Alternatively, we could force
long format if the attribute is set.

What do you think?

Will
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