Hi All,
I hope someone would be able to help me out here. I have a query
regarding what is documented and known as the prefix for the Link-Local
addresses. It is generally defined as FE80::/10 but looking at RFC2464 it
says in section 5.
5 Link-Local Addresses
The IPv6 link-local address [AARCH] for an Ethernet interface is formed by
appending the Interface Identifier, as defined above, to the prefix
FE80::/64.
10 bits 54 bits 64 bits
+----------+-----------------------+----------------------------+
|1111111010| (zeros) | Interface Identifier |
+----------+-----------------------+----------------------------+
Here the prefix is FE80::/64. I know that FE80::/10 and FE80::/64 are the
same and that in practice FE80::/10 currently means FE80:/64 with the node's
EUI-64 in the bottom 64 bits but what I am not sure is how the /64 is
achieved. Does the /64 refer to the 10 MSB bits + the 54 bits which are all
0 or does the /64 mean the 64 Interface identifier bits? Also why use either
FE80::/10 or FE80::/64 as the Link local address instead of having just one?
Thanks for the help
Gene
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