1) No, there is no 32 bit entry point. It expects to be executed at its
compiled address, with paging enabled, in long mode. This is quite different
to how the i386 kernel starts up.
2) It's not particularly fussy - but it does need V==P for the first 1GB or so,
and the 1GB that the kernel is executing in. I kept it simple for our loader
and mapped first 1GB of physical memory over the entire address space. All
slots of the 4th level page table point to the same level 3 page, which point
to the same level 2 page, which is full of 1:1 mappings for 2MB pages for the
first 1GB. This 12KB is discarded after very early in the bootstrap.
---
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