On 2010-09-29, at 1:20 PM, HASCALL, DAVID CIV DFAS wrote:

> I do not know how to figure out effective radiated power but I could see
> where 25Kw., directly NE of the station, would sound like 50 Kw., or
> better.
> 
> http://www.fcc.gov/ftp/Bureaus/MB/Databases/AM_DA_patterns/1355584-11043
> 2.pdf
> 


You are correct - effective radiated power works out to 81.6 kW
at an azimuth of 45 degrees (and 51.2 kW straight north)

73,

Deane McIntyre VE6BPO
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