Can you send the entire source code that sets “Something” and then the entire C# method that accesses it, ideally a minimal repro?
Tomas From: ironruby-core-boun...@rubyforge.org [mailto:ironruby-core-boun...@rubyforge.org] On Behalf Of Ivan Porto Carrero Sent: Wednesday, November 25, 2009 5:29 AM To: ironruby-core Subject: [Ironruby-core] invoke member and dynamic binding isn't the same? Hi I have some ruby code, which through a process of instance_eval and other meta programming tricks builds an object with a method assign defined on it. I have this code in C# var scope = Engine.CreateScope(); scope.SetVariable("ctxt", this); Engine.ExecuteFile("rubyfile.rb", scope); This code correctly sets a something property on this (linked with ctxt) but when I then want to call a method on it that should exist public dynamic Something { get; set; } Something.assign("ivan") Unhandled Exception: Microsoft.CSharp.RuntimeBinder.RuntimeBinderException: 'Iro nRuby.Builtins.RubyObject' does not contain a definition for 'assign' at CallSite.Target(Closure , CallSite , Object , String ) at System.Dynamic.UpdateDelegates.UpdateAndExecuteVoid2[T0,T1](CallSite site, T0 arg0, T1 arg1) at BugTracker_40.Bug.Assign(String assignee) in C:\dev\ironruby-in-action\Sam ples\BugTracker_40\BugTracker_40\Bug.cs:line 60 at BugTracker_40.Program.Main(String[] args) in C:\dev\ironruby-in-action\Sam ples\BugTracker_40\BugTracker_40\Program.cs:line 13 However the same code with: var _rubyOperations = Engine.CreateOperations() public object Something { get; set; } _rubyOperations.InvokeMember(Something, "assign", "ivan") does work. The question is why? Is this the expected behavior? Am I missing an assembly reference (it has Ironruby.*, Microsoft.Scripting, Microsoft.Scripting.Core) --- Met vriendelijke groeten - Best regards - Salutations Ivan Porto Carrero Blog: http://flanders.co.nz Google Wave: portocarrero.i...@googlewave.com<mailto:portocarrero.i...@googlewave.com> Twitter: http://twitter.com/casualjim Author of IronRuby in Action (http://manning.com/carrero)
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