.skip() always returns the same number as given as parameter while the stream
itself may or may not skip to given position
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Key: VFS-218
URL: https://issues.apache.org/jira/browse/VFS-218
Project: Commons VFS
Issue Type: Bug
Affects Versions: 1.0
Environment: Java 5, using jdk1.6.0_06 on Windows XP SP3
Reporter: Not Telling
The code below should reproduce the bug, so far I've tested this with file: and
res: file systems and at least those two expose this bug. As you may notice
from the source, you should have file called "bla.txt" containing "blabla" (6
characters) in your C:\temp\ folder for this.
{code:title=VFSStreamSkipping.java}
import java.io.IOException;
import java.io.InputStream;
import org.apache.commons.vfs.FileObject;
import org.apache.commons.vfs.FileSystemException;
import org.apache.commons.vfs.FileSystemManager;
import org.apache.commons.vfs.VFS;
/**
* This class demonstrates buggy behaviour of .skip() when using VFS.
* The bug is that no matter how many bytes were actually skipped, .skip()
* always returns the same number as the user tried to skip. The stream itself
* may get skipped though, if one tries to read the stream in this example
* after .skip(), it will return -1 indicating that .skip() was executed
* properly.
*/
public class VFSStreamSkipping {
public static void main(String[] args) {
FileObject file;
FileSystemManager fsm;
try {
fsm = VFS.getManager();
} catch (FileSystemException e) {
fsm = null;
}
InputStream is = null;
try {
file = fsm.resolveFile("file:C:/temp/bla.txt");
// file content is simply "blabla" with no \n or \r
is = file.getContent().getInputStream();
} catch (FileSystemException e) {}
try {
long skipped = is.skip(9L);
System.out.println(skipped+" <= prints 9, this should
be 6 as per javadoc's specification; "+
"http://java.sun.com/j2se/1.5.0/docs/api/java/io/InputStream.html#skip(long)");
System.out.println(is.read());
} catch (IOException e) {}
}
}
{code}
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