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https://issues.apache.org/jira/browse/LANG-536?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=14172438#comment-14172438
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Duncan Jones commented on LANG-536:
-----------------------------------

bq. Whilst this is by no means complete (have only made the Javadoc changes and 
started the adaption to Iterators), this is what I had in mind on the train 
home with the IntegerIterator method at the bottom of the class.

I'm struggling to apply your patch successfully. I also notice (by glancing 
through the patch file) that you reference {{IteratorUtils}}, but this doesn't 
appear to be included in the patch files. Did you modify your pom to include a 
reference to Commons Collections?

Are you able to apply your own patch successfully to the trunk? I'm currently 
trying to use Eclipse's patching capabilities (via Team > Apply Patch...). I 
don't get any errors, but it's clear only parts of the patch were applied.

> Add isSorted() to ArrayUtils
> ----------------------------
>
>                 Key: LANG-536
>                 URL: https://issues.apache.org/jira/browse/LANG-536
>             Project: Commons Lang
>          Issue Type: New Feature
>          Components: lang.*
>            Reporter: Sergei Ivanov
>            Priority: Minor
>             Fix For: Review Patch
>
>         Attachments: LANG-536 partial.patch, LANG-536.patch, perftest.zip
>
>
> In my unit tests I often need to verify that an array is correctly sorted.
> In order to achieve this, I've got two helper methods as follows.
> Is it possible to integrate these methods into ArrayUtils?
> {code}
>     /**
>      * Checks that the specified array of objects is in an ascending order
>      * according to the specified comparator.  All elements in the array must 
> be
>      * <i>mutually comparable</i> by the specified comparator (that is,
>      * <tt>c.compare(e1, e2)</tt> must not throw a <tt>ClassCastException</tt>
>      * for any elements <tt>e1</tt> and <tt>e2</tt> in the array).
>      *
>      * @param a the array to be checked.
>      * @param c the comparator to determine the order of the array.  A
>      * <tt>null</tt> value indicates that the elements'
>      * {@linkplain Comparable natural ordering} should be used.
>      * @return {@code true}, if the array is sorted; {@code false}, otherwise.
>      * @throws ClassCastException if the array contains elements that are
>      * not <i>mutually comparable</i> using the specified comparator.
>      */
>     public static <T> boolean isSorted(final T[] a, final Comparator<? super 
> T> c) {
>         if (a.length <= 1) {
>             // Empty or singleton arrays are always sorted
>             return true;
>         }
>         // Otherwise, check that every element is not smaller than the 
> previous
>         T previous = a[0];
>         for (int i = 1, n = a.length; i < n; i++) {
>             final T current = a[i];
>             if (c.compare(previous, current) > 0) {
>                 return false;
>             }
>             previous = current;
>         }
>         return true;
>     }
>     /**
>      * Checks that the specified array of objects is in an ascending order,
>      * according to the {@linkplain Comparable natural ordering} of its 
> elements.
>      * All elements in the array must implement the {@link Comparable} 
> interface.
>      * Furthermore, all elements in the array must be <i>mutually 
> comparable</i>
>      * (that is, <tt>e1.compareTo(e2)</tt> must not throw a 
> <tt>ClassCastException</tt>
>      * for any elements <tt>e1</tt> and <tt>e2</tt> in the array).
>      *
>      * @param a the array to be checked.
>      * @return {@code true}, if the array is sorted; {@code false}, otherwise.
>      * @throws ClassCastException if the array contains elements that are not
>      * <i>mutually comparable</i> (for example, strings and integers).
>      */
>     @SuppressWarnings({"unchecked"})
>     public static <T> boolean isSorted(final T[] a) {
>         if (a.length <= 1) {
>             // Empty or singleton arrays are always sorted
>             return true;
>         }
>         // Otherwise, check that every element is not smaller than the 
> previous
>         T previous = a[0];
>         for (int i = 1, n = a.length; i < n; i++) {
>             final T current = a[i];
>             if (((Comparable<? super T>) previous).compareTo(previous) > 0) {
>                 return false;
>             }
>             previous = current;
>         }
>         return true;
>     }
> {code}



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