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https://issues.apache.org/jira/browse/HBASE-21291?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=16646891#comment-16646891
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stack commented on HBASE-21291:
-------------------------------
Thanks [~tianjingyun]. Can you manufacture the state in a test? Thank you.
> Bypass doesn't work for state-machine procedures
> ------------------------------------------------
>
> Key: HBASE-21291
> URL: https://issues.apache.org/jira/browse/HBASE-21291
> Project: HBase
> Issue Type: Bug
> Affects Versions: 2.2.0
> Reporter: Jingyun Tian
> Assignee: Jingyun Tian
> Priority: Major
>
> {code}
> if (!procedure.isFailed()) {
> if (subprocs != null) {
> if (subprocs.length == 1 && subprocs[0] == procedure) {
> // Procedure returned itself. Quick-shortcut for a state
> machine-like procedure;
> // i.e. we go around this loop again rather than go back out on
> the scheduler queue.
> subprocs = null;
> reExecute = true;
> LOG.trace("Short-circuit to next step on pid={}",
> procedure.getProcId());
> } else {
> // Yield the current procedure, and make the subprocedure runnable
> // subprocs may come back 'null'.
> subprocs = initializeChildren(procStack, procedure, subprocs);
> LOG.info("Initialized subprocedures=" +
> (subprocs == null? null:
> Stream.of(subprocs).map(e -> "{" + e.toString() + "}").
> collect(Collectors.toList()).toString()));
> }
> } else if (procedure.getState() == ProcedureState.WAITING_TIMEOUT) {
> LOG.debug("Added to timeoutExecutor {}", procedure);
> timeoutExecutor.add(procedure);
> } else if (!suspended) {
> // No subtask, so we are done
> procedure.setState(ProcedureState.SUCCESS);
> }
> }
> {code}
> Currently implementation of ProcedureExecutor will set the reExcecute to true
> for state machine like procedure. Then if this procedure is stuck at one
> certain state, it will loop forever.
> {code}
> IdLock.Entry lockEntry =
> procExecutionLock.getLockEntry(proc.getProcId());
> try {
> executeProcedure(proc);
> } catch (AssertionError e) {
> LOG.info("ASSERT pid=" + proc.getProcId(), e);
> throw e;
> } finally {
> procExecutionLock.releaseLockEntry(lockEntry);
> {code}
> Since procedure will get the IdLock and release it after execution done,
> state machine procedure will never release IdLock until it is finished.
> Then bypassProcedure doesn't work because is will try to grab the IdLock at
> first.
> {code}
> IdLock.Entry lockEntry =
> procExecutionLock.tryLockEntry(procedure.getProcId(), lockWait);
> {code}
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