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https://issues.apache.org/jira/browse/HBASE-21291?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Jingyun Tian updated HBASE-21291:
---------------------------------
    Attachment: HBASE-21291.master.001.patch

> Add a test for bypassing stuck state-machine procedures
> -------------------------------------------------------
>
>                 Key: HBASE-21291
>                 URL: https://issues.apache.org/jira/browse/HBASE-21291
>             Project: HBase
>          Issue Type: Bug
>    Affects Versions: 2.2.0
>            Reporter: Jingyun Tian
>            Assignee: Jingyun Tian
>            Priority: Major
>         Attachments: HBASE-21291.master.001.patch
>
>
> {code}
>       if (!procedure.isFailed()) {
>         if (subprocs != null) {
>           if (subprocs.length == 1 && subprocs[0] == procedure) {
>             // Procedure returned itself. Quick-shortcut for a state 
> machine-like procedure;
>             // i.e. we go around this loop again rather than go back out on 
> the scheduler queue.
>             subprocs = null;
>             reExecute = true;
>             LOG.trace("Short-circuit to next step on pid={}", 
> procedure.getProcId());
>           } else {
>             // Yield the current procedure, and make the subprocedure runnable
>             // subprocs may come back 'null'.
>             subprocs = initializeChildren(procStack, procedure, subprocs);
>             LOG.info("Initialized subprocedures=" +
>               (subprocs == null? null:
>                 Stream.of(subprocs).map(e -> "{" + e.toString() + "}").
>                 collect(Collectors.toList()).toString()));
>           }
>         } else if (procedure.getState() == ProcedureState.WAITING_TIMEOUT) {
>           LOG.debug("Added to timeoutExecutor {}", procedure);
>           timeoutExecutor.add(procedure);
>         } else if (!suspended) {
>           // No subtask, so we are done
>           procedure.setState(ProcedureState.SUCCESS);
>         }
>       }
> {code}
> Currently implementation of ProcedureExecutor will set the reExcecute to true 
> for state machine like procedure. Then if this procedure is stuck at one 
> certain state, it will loop forever.
> {code}
>           IdLock.Entry lockEntry = 
> procExecutionLock.getLockEntry(proc.getProcId());
>           try {
>             executeProcedure(proc);
>           } catch (AssertionError e) {
>             LOG.info("ASSERT pid=" + proc.getProcId(), e);
>             throw e;
>           } finally {
>             procExecutionLock.releaseLockEntry(lockEntry);
> {code}
> Since procedure will get the IdLock and release it after execution done, 
> state machine procedure will never release IdLock until it is finished.
> Then bypassProcedure doesn't work because is will try to grab the IdLock at 
> first.
> {code}
>     IdLock.Entry lockEntry = 
> procExecutionLock.tryLockEntry(procedure.getProcId(), lockWait);
> {code}



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