sunhelly commented on pull request #3260:
URL: https://github.com/apache/hbase/pull/3260#issuecomment-840323482
> I think even with only 1 table, we could still compute the table skew
count?
>
> For example, we have a table with 100 regions, and there are 3 region
servers, but all the regions are placed on a single server?
Hi, @Apache9 , when there is only 1 table, just like balance by table (the
cluster state only contains distribution info of exactly one table and all the
online RSes), the RegionCountSkewCostFunction can replace the
TableSkewCostFunction. For the example of [100,0,0], the cost of
RegionCountSkewCostFunction is 1, which will generate balance actions in the
next steps.
But when the table regions has already been evenly distributed, for example
[1,0,0,0], the cost of TableSkewCostFunction will not be 0, it is 1(the cost of
RegionCountSkewCostFunction is 0), but the table does not need to be balanced,
it brings many redundant computation steps of actions.
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