szehon-ho commented on issue #11800:
URL: https://github.com/apache/iceberg/issues/11800#issuecomment-2564342146

   I think there are two 'not matched' here, 
   1 ) entries in A not matched in B
   2) entries in B not matched in A.  
   
   Case (1) is do-able.
   For case (2), it is harder because each of the replicate partitions only 
gets a partial view of the split side.  Say:
   <pre>
   TableA(split)       TableB (replicate)            
   (1, a)                     (1, a)
   (2, b)                     (1, a)
   </pre>
   
   The second pair (2, b) vs (1, a) will wrongly calculate that TableB has a 
non-match with TableA and return (1,a).  But actually it match in the first 
pair.
   
   Hope that makes sense.


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