samredai commented on code in PR #4466:
URL: https://github.com/apache/iceberg/pull/4466#discussion_r851551000
##########
python/src/iceberg/expressions/base.py:
##########
@@ -122,3 +125,139 @@ def __le__(self, other):
def __ge__(self, other):
return self.value >= other.value
+
+
+class BooleanExpression(ABC):
+ """base class for all boolean expressions"""
+
+ @abstractmethod
+ def __invert__(self) -> "BooleanExpression":
+ ...
+
+
+class And(BooleanExpression):
+ """AND operation expression - logical conjunction"""
+
+ def __new__(cls, left: BooleanExpression, right: BooleanExpression, *rest:
BooleanExpression):
+ if rest:
+ return reduce(And, (left, right, *rest))
+ if left is AlwaysFalse() or right is AlwaysFalse():
+ return AlwaysFalse()
+ elif left is AlwaysTrue():
+ return right
+ elif right is AlwaysTrue():
+ return left
+ return super().__new__(cls)
+
+ def __init__(
+ self,
+ left: BooleanExpression,
+ right: BooleanExpression,
+ *rest: BooleanExpression,
+ ):
+ if not rest:
+ self.left = left
+ self.right = right
Review Comment:
> But \_\_init\_\_ still exists and can be called directly.
I don't think there's a way to do this while avoiding a call to `__new__`.
The one way I wasn't sure of was if a child class calls init via super but I
did this quick test and even that calls `__new__`.
```py
class Foo:
def __new__(cls):
print("New called")
return cls
def __init__(self, val):
self.val = val
class Bar(Foo):
def __init__(self):
super().__init__(5)
Bar() # "New called"
```
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