tanruixiang commented on PR #849: URL: https://github.com/apache/incubator-kvrocks/pull/849#issuecomment-1253977736
> > > > > Hi. When we parse `"a''b"`, May I ask which of the following is in line with expectations. `"a''b"` => `"ab"` `"a''b"` => `"a''b"` The code parses out the second case. > > > > > > > > > if you mean `key "a''b"`, the result will be `key`, `a''b`. > > > > > > Yes. I mean Is it necessary to treat `''` as null？For the current code, parse `"a\'\'b"`'s reusult is equal to `"a''b"`. > > There is no programming language / shell language / markup language treat `'` as null in a quoted string started with `"`. Sorry, I made a mistake. Hope it didn't bother you -- This is an automated message from the Apache Git Service. To respond to the message, please log on to GitHub and use the URL above to go to the specific comment. To unsubscribe, e-mail: [email protected] For queries about this service, please contact Infrastructure at: [email protected]
